-7x^2+5x+48=0

Solution for -7x^2+5x+48=0 equation:

-7x^2+5x+48=0

a = -7; b = 5; c = +48;
Δ = b2-4ac
Δ = 52-4·(-7)·48
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-37}{2*-7}=\frac{-42}{-14}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+37}{2*-7}=\frac{32}{-14}
=-2+2/7
$